We use essential cookies to perform essential website functions, e.g. Last updated: Fri Oct 20 12:50:46 EDT 2017. eval(ez_write_tag([[300,250],'programcreek_com-medrectangle-4','ezslot_2',137,'0','0'])); public List
Instantly share code, notes, and snippets. Yeah, there are a lot of ways to do this. You have three sets of numbers you need to generate.
DFS problems are very similar and can be solved by using a simple recursion. With the code written the way it is now, I do get the country code but the problem is that the length is confined to 1 or 2 digits. Is there a command to find out the numerical length of the PhoneNumber String? We're a friendly, industry-focused community of List
temp.add(new StringBuilder(l.get(j)).append(option.charAt(p)).toString()); you already have all the pieces to do it in front of you, you just need to put them together. List
3. 2. then the area code substring needs to be composed of whatever is right after the first dash to the character before the second dash and That will only be the case if you enter it in the form 1-whatever. PhoneNumber code in Java. For more information, see our Privacy Statement. Add 1 to that number to ensure that it can never be 0. Thayland, Why do you seem to think the character at that index is 1? :). There are a few formats available (under PhoneNumberFormat), and the format_number function does the formatting.
I just bet there is an easy simple way to code this problem and I'm just not catching on. } I turned it in and only got partial credit. char[] arr = new char[digits.length()]; This says, generate a random number between 0 and 6. I've been working on a problem from my Intro to Java class for a couple of weeks and I feel like I'm close. } Learn more. dict.put('8',new char[]{'t','u','v'}); Here i provide a regex pattern to determines if the phone number is in correct format, the pattern force starting with 3 digits follow by a “-” and 7 digits at the end. Here's the actual directions: "Write an application that creates and prints a random phone number of the form XXX-XXX-XXXX. if (digits == null || digits.length() == 0) {
dict.put('9',new char[]{'w','x','y','z'});
} I just hope that your patience doesnt run out with me. Which I did! Reach out to all the awesome people in our software development community by starting your own topic. return l;
result.add(new String(arr)); 6.
import java.util. char number = digits.charAt(index); and space is O(m) m= number of unique combinations for every recursive calls. We use optional third-party analytics cookies to understand how you use GitHub.com so we can build better products. ArrayList
[needs i18n work] Example usage: return result; The happy number can be defined as a number which will yield 1 when it is replaced by the sum of the square of its digits repeatedly. \\d{3}-\\d{7} for (int j = 0; j < l.size(); j++) { This problem can be solves by a typical DFS algorithm. What is the time complexity of this ? Am I going about this the hard way? PhoneNumber code in Java. Copyright © 2000–2017, Robert Sedgewick and Kevin Wayne. We use optional third-party analytics cookies to understand how you use GitHub.com so we can build better products. In this program, we need to determine whether a given number is a happy number or not. That will only be the case if you enter it in the form 1-whatever. This encourages use of the format method to output the telephone number in any style the programmer wishes. Here goes: This program allows a user to enter a phone number, country code, area code, and local number. That index, which you already calculated, is the variable "sep" in the code you posted, minus 1. I turned it in and only got partial credit. Why do you seem to think the character at that index is 1? } It then stores the telephone number internally in seperate codes (area code, exchange, etc.). your solution is much better . dict.put('5',new char[]{'j','k','l'}); }. I know the solution is probably obvious to you regular Javanauts, but I'm a beginner if you couldn't tell.
The catch is that in some countries, the length of each string can vary. Last updated: Fri Oct 20 14:12:12 EDT 2017. String option = map.get(digits.charAt(i)); I know what you are saying. What I was thinking of was making each character in the PhoneNumber string into a substring PhoneCharacter(x) and then run each character through a loop and assign CountryCode, AreaCode and LocalNumber the contents of whatever, and however many characters where between the dashes. Since you determined that your '-' is at phoneNumber.indexOf("-"), the next part of your phoneNumber is going to …. You know the index that the area code ends at. Since you know the index the area code ends at, (sep), sep + 1 is the first index of "local".
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The first number has the most requirements. return result; I totally appreciate your hints and help more than you can imagine. arr[index]=candidates[i]; } Time complexity is O(k^n), where k is the biggest number of letters a digit can map (k=4) and n is the length of the digit string. You already figured out how to get the countryCode. for (int p = 0; p < option.length(); p++) { l.addAll(temp); } map.put('5', "jkl");
}
return l; You ensure it will always be greater than 100 by using: (rand.nextInt(7)+1) * 100.
(Check out your cellphone to see the mappings) Input:Digit string "23", Output: ["ad", "ae", "af", "bd", "be", "bf", "cd", "ce", "cf"]. Minus one because the size of the string might be 10, but it will be indexed by 0-9. dict.put('4',new char[]{'g','h','i'}); Consider the following: 1.
// Sequence two of phone number // the plus 100 is so there will always be a 3 digit number // randomize to 643 because 0 starts the first placement so if i … 2. *; import java.lang. l.add(""); That index is phoneNumber.indexOf('-') + 1. }, I think it’s not O(n^n) but O(m^n) where m is max number of letters possible for one digit and n is number of digits, so in case of keypad it’s O(4^n), I think it’s O(n^n) n = number of digits However, the Prof decided to test my program with three digits in the Country Code and everything went whacky from there. char[] candidates = dict.get(number); map.put('3', "def"); map.put('7', "pqrs"); map.put('2', "abc"); public List
Here goes: This program allows a user to enter a phone number, country code, area code, and local number.
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